Math153
J. Dykacz
4/30/01 Extra Review Problems Test 3 (BLUE)
1.
Assume
that the mean hourly wage in a traditionally female occupation is $10 per hour
( m
=10). Men have entered the occupation,
and we want to test how the mean hourly wage for males compares with the
$10. A random sample of 36 males is
taken; the sample mean is $10.90 and the sample standard deviation is $3.
a)
At
the 5% significance level, is the mean hourly wage for males $10 or is it
different from $10?
H0: ________________________
Ha: ________________________
1. a = _______
2. Test statistic: ________________ p-value: ____________________
3. Conclusion: ____________________________________________
b)
At
the 5% significance level, is the mean hourly wage for males greater than $10?
H0: ________________________
Ha: ________________________
1. a = _______
2. Test statistic: ________________ p-value: ____________________
3. Conclusion: ____________________________________________
c)
At
the 1% significance level, is the mean hourly wage for males greater than $10?
H0: ________________________
Ha: ________________________
1. a = _______
2. Test statistic: ________________ p-value: ____________________
3. Conclusion: ____________________________________________
2.
A
researcher wants to estimate the average number of cigarettes smoked per day by
teenage boys who are smokers. Assume a
99% confidence interval will be calculated with a margin of error of not more
than 0.5 (1/2 a cigarette). Assume that
the standard deviation is 2.7. Find the
appropriate sample size.
3.
A
poll is to be conducted among a sample of students at a college to determine if
they are satisfied (or not) with extracurricular activities. A 90% confidence interval is to be formed of
the percent of students who are satisfied with extracurricular activities; the
margin of error should be no more than 5%..
a)
From
a previous study, the percent was 63%.
Find the appropriate sample size.
b) Assume that no previous, related study was
done. Find the appropriate sample size.
Answers
1a)
H0 : m =10
Ha : m
10
1. a=.05
2. t =1.80, p-value=.0805
3.
Do not reject H0
1b)
H0 : m
10
Ha : m >10
1. a=.05
2. t = 1.80, p-value=.0402
3.
Reject H0
1c)
H0 : m
10
Ha : m >10
1. a=.01
2. t = 1.80, p-value=.0402
3.
Do not reject H0
2 n =
=
= 193.349025 = 194
3. a) n =
=
= 252.309771 = 253
b) n =
=
= 270.6025 = 271